98u=-16u^2-12

Solution for 98u=-16u^2-12 equation:

98u=-16u^2-12

We move all terms to the left:

98u-(-16u^2-12)=0

We get rid of parentheses

16u^2+98u+12=0

a = 16; b = 98; c = +12;
Δ = b2-4ac
Δ = 982-4·16·12
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-94}{2*16}=\frac{-192}{32}
=-6
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+94}{2*16}=\frac{-4}{32}
=-1/8
$